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scienceJul 4, 202513:48pending

OEIS A000267: Floor of sqrt(4n+1)

About this episode

We explore A000267, the deceptively simple a(n) = floor(sqrt(4n+1)). Beyond the bare rule lies a repeating pattern where each integer k occurs floor(2k+3) times, a connection to odd squares, and a web of alternate characterizations—from algebraic identities and recursive definitions to divisor-counting viewpoints and diagonal readings of triangle A094727.


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OEIS A000267: Floor of sqrt(4n+1)

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